Originally Posted by KalterTod

These problems are all about visualizing simpler ways to essentially "break down" what you're looking at.

For example, in problem A, you have a square and a semi-circle. Since you know the sides of the square are all 5cm, you can also deduce that the radius of the circle is 2.5 cm because its diameter is also 5 cm.

To find the area, it is simple: 1/2*pi*r^2(r=2.5) + 5^2

For a more complicated example, look at problem F. The total area shown is 1/2*pi*r^2, but you are also omitting a smaller section of the semi-circle.

You can break up the omitted section into a triangle, and a trapezoid.

Much like the last problem, only with an omission instead of an addition, your formula should be: 1/2*pi*r^2 - (1/2*s1*s2) - 1/2(b1+b2)h

s1, s2: side1 and side2; b1, b2: base 1 and base 2.

I'm sure you know the formulae for these more simple shapes, but I figured I would point this out anyway.

This should at least give you a solid start on your assignment. Any questions, feel free to post/PM.