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Originally Posted by Nugwin  I solved it, but I have a another one.
Sam shot his model rocket up into the air and counted the seconds it stayed in flight. He noticed that the rocket seemed to be at the same height as the top of a television antenna at 3 and 6 seconds. Find the initial speed of the model rocket and the height of the television antenna. |
Yeah...it's just a manipulation of the formula that v(final)=v(start)+at. It's actually the derivative of that equation.
As for your problem...you could deduce the fact that the rocket would reach its zenith at 4.5 seconds. So, without going through the problem, you could use the acceleration due to gravity on earth, and the 4.5 seconds that you know, as well as the final velocity being zero because it's at a zenith, to find the starting velocity.