#1 (permalink)

Yeah, I am really lost, anyone want to do some of these for me?

| is going to be the square root symbol, because I don't have that symbol on my keyboard, lol.

1. |28 + |63
2. |44 - |11
3. |14 - |2/7
4. 2|32 + 3|50 - 3|18

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#2 (permalink)

Haha. I was like oh yeah this should be easy. Then I was like, hmmm, haven't done this for a long long time.

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#3 (permalink)

I left my algebra book at school because we didn't have class today. If I had it I could look it up and help you

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#4 (permalink)

I think you just add them normally like....

1. l28l + 63 would be l91l

I think but I am not sure exactly.

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#5 (permalink)

Noooo...Thats exactly what you are NOT supposed to do. Its like adding x's and y's.

Simplify each radical...then, when there are similar radicals (ex. two or more terms with a "square root 2") and add them together...

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#6 (permalink)

Shmads is Smart™

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#7 (permalink)

Math is my worst subject. I still get an A but I just hate it oh so much.

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#8 (permalink)

ya im having the exact same problem. this whole radical thing is not making any sense at all

#9 (permalink)

Shmads is right- you CAN NOT simply add them together, you must simplify first. The easiest way to see this is to break everything down into it's Prime Factorizations.

squ(28) + squ(63) = squ(4 * 7) + squ(9 * 7)

From here, you can pop out a 4 from the first radical, and 9 from the other, turning the problem into...

2*squ(7) + 3*squ(7) = 5*squ(7)

Simply enough, right?

As far as the others....

2.) squ(44) - squ(11) = squ(4*11) - squ(11) = 2*squ(11) - squ(11) = squ(11)

3.) squ(14) - squ(2/7) = squ(14) - squ(14/49) [simply multiply the top and bottom by 1, in the form of 7/7] = squ(14) - 1/7 *squ(14) = 6/7 * squ(14)

4.) 2*squ(32) + 3*squ(50) - 3*squ(18) = 2*squ(16*2) + 3*squ(25*2) - 3*squ(9*2) = 8*squ(2) + 15*squ(2) - 9*squ(2) = 14*squ(2)

There you go. Should make sense.

#10 (permalink)

I will solve one problem. You can then do the rest on your own using my notes.

Let sqrt{ } = square root

(1) sqrt{28} + sqrt{63}

Take sqrt{28}. The first thing you want to ask yourself is:

What two numbers (one of the numbers must be a perfect square) when multiplied together will produce 28?

How about 7 x 4? Yes, 7 x 4 = 28 and 4 is a perfect square because 2 x 2 = 4.

Now, 7 is not a perfect square because there aren't any SAME NUMBERS that when multiplied together will produce 7. Is this clear?

We now house 7 and 4 into separate square roots.

sqrt{7} and sqrt{4}

Of course, the square root of 4 is 2. The square root of 7 is already in lowest terms and so, we leave it alone.

We now have 2(sqrt{7}).

We now have to simplify sqrt{63} the same way.

What two numbers (one of the numbers must be a perfect square) when multiplied together will produce 63?

How about 9 x 7?

Yes, 9 x 7 = 63 and 9 is a perfect square
because 3 x 3 = 9.

sqrt{9} and sqrt{7}

The square root of 9 is 3.

We now have 3(sqrt{7}.

=================

This is what we have now:

2(sqrt{7}) + 3(sqrt{7})

The idea in terms of addition and subtraction of radicals is to get the SAME RADICAND all terms. Notice that each term has a sqrt{7}. See it?

We now simply add 2 + 3 and include sqrt{7} in your answer.

Final answer: 5(sqrt{7})...This is read: "Five times the square root of seven."

Is this clear?