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| | Skinny Nerd Join Date: Jun 2007
Posts: 66
|  Summer Homework Help :
08-21-2007
Well, I start school tomorrow, and I need some help finishing this.
It is mostly pre-calc. stuff.
f(x)= {(3,5), (2,4), (1,7)}
g(x)= square root of x-3
h(x)= {(3,2), (4,3), (1,6)}
k(x)= x^2 + 5
So, with that information what would (f + h)(1) = ?
How would I go about doing that?
What do I add?
What does the 1 stand for?
Last edited by Crafty; 08-21-2007 at 01:06 PM.
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 | | | Skinny Nerd Join Date: Jun 2007
Posts: 66
|
08-21-2007
Another one.
Expand (x+y)^3
I just don't remember how to expand. |
| | | Never does his homework Join Date: Jun 2007 Location: Utah
Posts: 1,853
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08-21-2007
Calculus...im only in geometry and then im done with math
i have no idea what you are talking about |
| | | Beats up Foreign Ex Students Join Date: Jun 2007 Location: Pennsylvania
Posts: 2,161
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08-21-2007
Then don't post in the thread. If you can't help him why bother posting? You are getting desperate for those +1s now. |
| | | Never does his homework Join Date: Jun 2007 Location: Utah
Posts: 1,853
|
08-21-2007
I think he is the only one here who is in Calculus.
JMK=Spam |
| | | Beats up Foreign Ex Students Join Date: Jun 2007 Location: Remembering...
Posts: 2,101
|
08-21-2007
Only one who's in Calc eh?
Sorry Crafty but I forget all this shit, yet I'm AP Calc BC lolz.
__________________ Quote:
Originally Posted by Nastadon  28) wtf is a coat hanger? | |
| | | Skinny Nerd Join Date: Jun 2007 Location: St. Louis
Posts: 69
|
08-21-2007
Quote:
Originally Posted by Git Only one who's in Calc eh?
Sorry Crafty but I forget all this shit, yet I'm AP Calc BC lolz. | With your grammar, it seems your math equivalent would be pre-algebra. Crafty, if you need help, just aim me.
__________________
Let's keep this professional. |
| | | Beats up Foreign Ex Students Join Date: Jun 2007 Location: Remembering...
Posts: 2,101
|
08-21-2007
Ah, you're the funny H3F kid who always makes fun of iKaRiZzMa.
Well, at least SOME people like me here.
__________________ Quote:
Originally Posted by Nastadon 28) wtf is a coat hanger? |
Last edited by Git; 08-21-2007 at 04:45 PM.
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| | | Beats up Foreign Ex Students Join Date: Jun 2007 Location: Pennsylvania
Posts: 2,161
|
08-21-2007
Quote:
Originally Posted by Git Well, at least SOME people like me here. | Who's that?
♥♥♥ |
| | | The New Kid Join Date: Aug 2007 Location: B-LO, NY
Posts: 29
|
08-23-2007
Quote:
Originally Posted by Crafty Well, I start school tomorrow, and I need some help finishing this.
It is mostly pre-calc. stuff.
f(x)= {(3,5), (2,4), (1,7)}
g(x)= square root of x-3
h(x)= {(3,2), (4,3), (1,6)}
k(x)= x^2 + 5
So, with that information what would (f + h)(1) = ?
How would I go about doing that?
What do I add?
What does the 1 stand for? | Basically, whenever you have something in the form of f(x) = 4x, find f(1), it means you substitute 1 in for x. Therefore when you have (f + g)(1), add f and g together, then substitute x=1 into the equation to find your answer. Quote: |
Originally Posted by Crafty Another one.
Expand (x+y)^3
I just don't remember how to expand. | For this one, there's two methods.
First, use something called Pascal's Triangle. Here it is:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
.
.
.
What this means is that your exponent corresponds to the second number in each row, then those are your coefficients. Therefore, (x + y)^3 =
1(x^3) + 3(x^2) y + 3x(y^2) + 1(y^3).
So start with x's as your high exponent, then reduce it by one every time you go to the next number.
The other way is to use combinations. In your calculator, go to the section with probability, and this time you will use the nCr tool. To find the coefficients, do the following:
3nCr0, 3nCr1, 3nCr2, 3nCr3. You use three because it's the exponent. Then follow the method of reducing exponents by one for x every time and increasing by one for y every time. |
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