#1 (permalink)

How many milliliters of 3.106 M KOH are required to make 14.9 L of a solution containing 0.251 g KOH per liter?
i want to know the steps to solve this problem
thanks

#2 (permalink)

.251 g per liter

.251 x 14.9 = 3.7399 grams are needed to make a 14.9 gram solution have .251 grams per liter.

KOH is 56 grams per mole, so a 3.106 M solution has 173.936 grams per liter.

You need to only take enough to have 3.7399 grams of KOH. So, do this:
3.7399 / 173.936 = x / 100
373.99 = 173.936x
x = 2.1501 % of a liter of the 3.106 M solution is needed
.021501 x 1000 = 21.504 mL

That should be right, but i'm not 100%.

#3 (permalink)

Great that you answered his question but...it was from October of last year.

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#4 (permalink)

Haha, WOW, you're right...I didn't even notice - and I usually check topic dates, oh well.

#5 (permalink)

Great to have you round though so you can actually help people when they need it

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#6 (permalink)