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Not sure about how line 5 simplifies to line 6 (there are just too many trig identities... lol I only know the basic ones), but I can see the line 3 was not squared but multiplied by the numerator/numerator:
[ tan (x / 2) + 1 ]/[ tan (x / 2) + 1 ]
so the denominator followed the rule such that (5-x)(5+x) = 25-x^2
LHS = [sec^2 (x / 2) + 2tan ( x / 2) ] / (1 - tan^2 (x / 2) )
LHS = [ 1 + 2 sin (x / 2) cos( x / 2) ] / cos x
I think I got it...
By identity for denominator sec^2(x) + tan^2(x) = 1
sec^2(x/2)/(sec^2(x/2)) = 1
and 2 tan (x/2)/(sec^2(x/2)) = 2 sin (x / 2) cos( x / 2)
I can't seem to think where the bottom cos (x) is coming from though I don't have paper to think clearly.. could be something to do with half angles or something since the bottom is not cos(x/2) but cos (x)
Hm. I guess I'll just work through this some more tomorrow in the library when I can think a little better. Thanks so far, and I'll get back to you tomorrow and see if I get it any better.